JSON筛选, 谢谢,

发布***

//这是新菜单从下面的旧菜单筛选出来的请问怎么做成这样//新菜单从旧菜单筛选出来的varnewMenuListJSonStr=[{"title":"实时监测","icon":"new/t-1","spread":true,"children":[{"title":"用能分布可视化","iconCls":"thirdLevelMenu/57","href":"energyMonitor/energyDistributionVisual"},{"title":"变配电监测","icon":"thirdLevelMenu/56","href":"energyMonitor/byqSVGMonitor"}]}];//旧菜单varoldData=[{"iconCls":"new/t-1","id":"4754406","name":"实时监测","pid":"0","subFunctionMenuList":[[{"iconCls":"c_sbjb","id":"4754407","name":"能耗可视化管理","pid":"4754406","subFunctionMenuList":[[{"iconCls":"thirdLevelMenu/57","id":"4754408","name":"用能分布可视化","pid":"4754407","subFunctionMenuList":[[]],"url":"energyMonitor/energyDistributionVisual"},{"iconCls":"thirdLevelMenu/56","id":"4754467","name":"变配电监测","pid":"4754407","subFunctionMenuList":[[]],"url":"energyMonitor/byqSVGMonitor"}]],"url":"energyMonitor"}]],"url":"/"}];

m8854***

谢邀请，我也没有筛选过 json 数据，我是这样想的，先创建一个空的对象，如：

var newMenuListJSonStr = [
{
"title" : "",
}
];

然后遍历旧的 json 数据，将旧数据赋值新的空对象

newMenuListJSonStr[0].title = oldData[0].name
newMenuListJSonStr[0].title //实时监测

看看别的大神是否这样做的？请告知。

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JSON筛选, 谢谢,

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